Draw one Lewis structure (including all bonds and all non-bonding electron pairs/lone pairs) of BrO 3 − ​ (bromate ion) that follows the octet rule. Determine the number of valence electrons in the molecule. Predict the ideal bond angles. Determine the electron group and molecular geometry according to the VSEPR method for the bromine atom.
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Answer

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Step 1
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Step 2
: Determine the total number of valence electrons

Total valence electrons: $$7 + 18 + 1 = 26$$ electrons
- Bromine (Br): 7 valence electrons - Oxygen (O): 6 valence electrons × 3 = 18 valence electrons - Negative charge: + 1 electron

Final Answer

The Lewis structure of BrO_{3}^{-} follows the octet rule with: - 26 total valence electrons - Tetrahedral electron geometry - Trigonal pyramidal molecular geometry - Ideal bond angle of 109.5°