Draw the Lewis structure for the trisulfur $\left(\mathrm{S}_{3}\right)$ molecule. Be sure to include all resonance structures that satisfy the octet rule.
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Answer

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Step 1
: Identify the total number of valence electrons in the $\mathrm{S}_{3}$ molecule.

\text{Total valence electrons} = 3 \times 6 = 18 \ \text{electrons}
Sulfur is in the 16th group of the periodic table, so it has 6 valence electrons.

Step 2
: Determine the central atom and arrange the atoms in a linear shape.

\mathrm{S}-\mathrm{S}-\mathrm{S}
In this case, all three sulfur atoms are identical, so we can choose any of them as the central atom. Let's choose the leftmost sulfur atom as our central atom. The arrangement of atoms will be:

Final Answer

The Lewis structure for the trisulfur $\left(\mathrm{S}_{3}\right)$ molecule, including all resonance structures that satisfy the octet rule, is shown below: : \mathrm{S}^{-} : \mathrm{S} : \mathrm{S}^{+} : \qquad \text{and} \qquad : \mathrm{S} : \mathrm{S}^{-} : \mathrm{S}^{+} :