"Draw the Lewis structure of BH^3 and then determine its electron domain and molecular geometries. A. trigonal / planar B. trigonal / tetrahedral C. trigonal planar / tetrahedral D. trigonal / bent (120°)"
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Answer

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Step 1
Let's solve this step by step:

Step 2
: Determine the total number of valence electrons

- Total valence electrons: $$3 + (1 \times 3) = 6$$ electrons
- Boron (B): 3 valence electrons - Hydrogen (H): 1 valence electron × 3 hydrogens

Final Answer

The key characteristics are: - 3 electron domains - Trigonal planar electron domain geometry - Trigonal planar molecular geometry - 120° bond angles