Calculate the 68%, 95%, and 99.7% confidence intervals for the sample proportions. Round all answers to the nearest ten-thousandth. 68% CI: _______ 95% CI: _______ 99.7% CI: _______ Use the Confidence Interval Formula: p \pm z \sqrt{\frac{p(1 -p)}{n}} Type your answers in the spaces provided.
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Answer

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Step 1
I'll solve this step by step using the confidence interval formula for proportions.

- Confidence Interval Formula: $$p \pm z \sqrt{\frac{p(1-p)}{n}}
Given: - We need to calculate 68%, 95%, and 99.7% confidence intervals

Step 2
: Identify the z-scores for different confidence levels

- 68% CI: z = 1 - 95% CI: z = 2 - 99.7% CI: z = 3

Final Answer

- 68% CI: p \pm 1 \sqrt{\frac{p(1 -p)}{n}} - 95% CI: p \pm 2 \sqrt{\frac{p(1 -p)}{n}} - 99.7% CI: p \pm 3 \sqrt{\frac{p(1 -p)}{n}}