Draw Lewis structures for each molecular formula: a. C₂H₄Cl₂ (two isomers) b. C₃H₈O (three isomers) c. C₃H₆ (two isomers)
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Answer

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Step 1
I'll solve this problem step by step, focusing on drawing Lewis structures for the given molecular formulas.

a. C₂H₄Cl₂ (two isomers)

Step 2
: Determine the total number of valence electrons

- Total valence electrons: $$8 + 4 + 14 = 26$$ electrons
- Carbon (C): 4 valence electrons × 2 = 8 - Hydrogen (H): 1 valence electron × 4 = 4 - Chlorine (Cl): 7 valence electrons × 2 = 14

Final Answer

- C₂H₄Cl₂: Two isomers (1,1 -dichloroethane and 1,2 -dichloroethane) - C₃H₈O: Three isomers (propan- 1 -ol, propan- 2 -ol, methoxyethane) - C₃H₆: Two isomers (propene and cyclopropane)