QQuestionAnatomy and Physiology
QuestionAnatomy and Physiology
"Draw the Lewis Dot Structure for BH^−2.
What is the electron geometry?
What is the molecular geometry?"
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Answer
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Step 1: Draw the Lewis structure for BH${}^{- 2}$.
H${}^{+}$ H${}^{-}$ H${}^{+}$ H${}^{-}$ H${}^{+}$
First, let's distribute the negative 2 charge to the hydrogen atoms, since boron cannot have a formal charge of + 1. This gives us three B-H bonds and two additional negative charges on two hydrogen atoms.
Step 2: Determine the total number of valence electrons.
3(B) + 6(H) + 2(extra) = 11
Boron has 3 valence electrons, and each hydrogen atom has 1 valence electron. In addition, there are 2 extra electrons from the charge. Therefore, the total number of valence electrons is:
Final Answer
The Lewis structure for BH${}^{- 2}$ is: B : H : H : H : H : H : : : : : : : : : : : : : : The electron geometry is trigonal bipyramidal, and the molecular geometry is trigonal planar.
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