**Triangle Inequality Theorem 1 (Ss → Aa)** – if one side of a triangle is longer than the second, then the angle opposite the longer side is larger than the angle opposite the second side. **Example:** Figure 1 shows a triangle with sides of different measures. List all angles of figure 1 in ascending order. *Figure 1 * **Solution:** By the Triangle inequality theorem 1, **MN** is the longest side and **xP**, the angle opposite **MN** is the largest angle. Also, since **MP** is the shortest side then **xp**, the angle opposite **MP** is the smallest angle. Hence, **xNxMxP**. Exercises: Given the figures below, arrange the angles in ascending order. 1. 2. 3.
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Answer

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Step 1
: Identify the longest side and the smallest side in each triangle.

In Triangle 1: - The longest side is **MN** since, by the Triangle Inequality Theorem 1, if one side of a triangle is longer than the second, then the angle opposite the longer side is larger than the angle opposite the second side. Here, side **MN** is longer than sides **MP** and **NP**. - The smallest side is **MP**. In Triangle 2: - The longest side is **XY** since it is longer than side **XZ**. - The smallest side is **XZ**. In Triangle 3: - The longest side is **PQ** since it is longer than side **PR**. - The smallest side is **PR**.

Step 2
: Identify the angles opposite the longest and smallest sides.

In Triangle 1: - The angle opposite the longest side **MN** is **x**. - The angle opposite the smallest side **MP** is **xp**. In Triangle 2: - The angle opposite the longest side **XY** is **α**. - The angle opposite the smallest side **XZ** is **xz**. In Triangle 3: - The angle opposite the longest side **PQ** is **θ**. - The angle opposite the smallest side **PR** is **pr**.

Final Answer

1. Triangle 1: xp < xN < xM 2. Triangle 2: xz < α < β 3. Triangle 3: pr < pr + θ