# Use the following equations to find the lattice energy of $M g C l_{2}$. Hint: First write the equation for the lattice energy of $\mathrm{MgCl}_{2}(s)$. 1. [tex] $\mathrm{Mg}(\mathrm{g})$ \rightarrow $\mathrm{Mg}^{2}(2 +)\left(\mathrm{g}+ 2 \mathrm{e}^{\wedge}-\right]$ 2. [tex] $\mathrm{Cl}(\mathrm{g})+\mathrm{e}^{\wedge}-\backslash$ rightarrow $\mathrm{Cl}^{\wedge}(\mathrm{g})$ ] 3. [tex] $\mathrm{Mg}(\mathrm{g})+ 2 \mathrm{Cl}(\mathrm{g})$ \rightarrow $\mathrm{MgCl}_{2}(s)$ ] Given values: - [tex] \Delta H = + 2188 , \text{kJ/mol] } - [tex] \Delta H = - 337 , \text{kJ/mol] } - [tex] \Delta H = - 642 , \text{kJ/mol] }
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Step 1
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Step 2
: Write the lattice energy equation

The lattice energy equation for $$\mathrm{MgCl}_{2}(s)$$ can be represented as:
\mathrm{Mg}^{2 +}(g) + 2\mathrm{Cl}^{-}(g) \rightarrow \mathrm{MgCl}_{2}(s)

Final Answer

The lattice energy of \mathrm{MgCl}_{2}(s) is - 872 \mathrm{~kJ/mol}.