Which equation is represented by the graph below? $y=\ln x$ $y=\ln x+ 1$ $y=e^{x}$ $x=e^{x}+ 1$
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Answer

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Step 1
: Identify the shape of the graph

This type of graph is represented by the equation $y = ae^{bx}$, where a and b are constants.
The given graph is an exponential curve that increases as x increases. However, the given options do not include this form. We need to find a transformation of this form that matches one of the given options.

Step 2
: Identify the asymptote

However, the given graph is not a reflection of $y = \ln x$ about the x-axis, so it cannot be $y = -\ln x$.
The exponential curve approaches the x-axis as x approaches negative infinity. This means that the x-axis is the horizontal asymptote of the curve.

Final Answer

The equation represented by the graph is $y = \ln x + 1$.