Use VSEPR theory to predict the electron-pair geometry and the molecular geometry of boron tribromide, BBr^3. (You will need to draw the Lewis structure to determine this.) A. The electron-pair geometry is trigonal-pyramidal; the molecular geometry is trigonal-pyramidal. B. The electron-pair geometry is trigonal-planar; the molecular geometry is trigonal-planar. C. The electron-pair geometry is trigonal-planar; the molecular geometry is bent. D. The electron-pair geometry is tetrahedral; the molecular geometry is trigonal-pyramidal. E. The electron-pair geometry is trigonal-pyramidal; the molecular geometry is T-shaped.
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Answer

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Step 1
I'll solve this step by step using VSEPR theory and proper LaTeX notation:

Step 2
: Draw the Lewis Structure

- Total valence electrons: $$3 + (3 \times 7) = 24$$ electrons
- Boron (B) is the central atom - Boron has 3 valence electrons - Each bromine (Br) has 7 valence electrons

Final Answer

The electron-pair geometry is trigonal-planar; the molecular geometry is trigonal-planar.