Write the quadratic function in the form $f(x)=a(x-h)^{2}+k$. Then, give the vertex of its graph. f(x)= 2 x^{2}+ 20 x+ 52 Writing in the form specified: $f(x)=\square$ Vertex: $(\square \square)$
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Answer

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Step 1
: Identify the values of a, h, and k in the given quadratic function.

- $h$ and $k$ are yet to be determined.

Step 2
: Completing the square to rewrite the function in the specified form.

f(2$)= 2(x+ 10 - 10)^{2}+ 52 + 2(10)^{2}- 2(10)^{2} Now, simplify the expression: f(2$)= 2(x+ 10)^{2}+ 52 + 40 - 200 f(2$)= 2(x+ 10)^{2}- 168

Final Answer

The quadratic function in the form $f(x)=a(x-h)^{2}+k$ is: f(x)= 2(x+ 10)^{2}- 168 The vertex of its graph is $(- 10, - 168)$.