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"After drawing the Lewis dot structure for CH^3Cl, determine the number of single bond(2$), double bond(2$), and lone pair(2$) on the central atom. Question 4 options: single bond(2$) = 4, double bond(2$) = 0, lone pair(2$) = 1 single bond(2$) = 4, double bond(2$) = 1, lone pair(2$) = 0 single bond(2$) = 3, double bond(2$) = 0, lone pair(2$) = 1 single bond(2$) = 4, double bond(2$) = 0, lone pair(2$) = 0 single bond(2$) = 3, double bond(2$) = 1, lone pair(2$) = 0"
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Answer

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Step 1
: Identify the central atom and its surrounding atoms in the Lewis structure.

The Lewis structure for CH^3Cl is: CH^3Cl H H H Cl The central atom here is carbon (C), surrounded by three hydrogen (H) atoms and one chlorine (Cl) atom.

Step 2
: Count the number of single bonds around the central atom.

In this Lewis structure, the central carbon atom forms four single bonds with the hydrogen and chlorine atoms. Therefore, single bond(s) = 4

Final Answer

The calculated values are: single bond(s) = 4 double bond(s) = 0 lone pair(s) = 0 Comparing these values with the given options, we find that the correct answer is: single bond(s) = 4, double bond(s) = 0, lone pair(s) = 0

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