QQuestionChemistry
QuestionChemistry
Calculate the mass of KHC^8H^4O^4 (molar mass = 204.23 g/mol) that reacts with 15 mL of 0.15 M NaOH.
Express this mass of KHC^8H^4O^4 to the correct number of significant figures.
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Answer
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Step 1: Write the balanced chemical equation for the reaction between KHC^8H^4O^4 and NaOH.
The balanced chemical equation is: \boxed{ \begin{aligned} \text{KHC}_8\text{H}_4\text{O}_4 + \text{NaOH} \rightarrow \text{KNaC}_8\text{H}_4\text{O}_4 + \text{H}_2\text{O} \end{aligned} }
Step 2: Calculate the number of moles of NaOH present in the solution.
Use the formula for molarity (M = n/V) to find the number of moles (n). Rearrange the formula to solve for n: \boxed{ \begin{aligned} n = \text{Molarity} \times \text{Volume (in liters)} \end{aligned} } Calculate the number of moles: \boxed{ \begin{aligned} n_{\text{NaOH}} &= 0.15 \text{ M} \times 0.015 \text{ L} \ &= 0.00225 \text{ mol} \end{aligned} }
Final Answer
The mass of KHC^8H^4O^4 that reacts with 15 mL of 0.15 M NaOH is 0.462 g.
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