Q
QuestionChemistry

Construct a Lewis structure for hydrogen peroxide, H^2O^2, in which each atom achieves a stable noble-gas electron configuration. Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons.
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Answer

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Step 1
I'll solve this Lewis structure problem step by step:

Step 2
: Determine the total number of valence electrons

- Total valence electrons: $$2 + 12 = 14$$ electrons
- Hydrogen (H): 1 electron × 2 atoms = 2 electrons - Oxygen (O): 6 electrons × 2 atoms = 12 electrons

Final Answer

The Lewis structure of hydrogen peroxide (H₂O₂) consists of a single bond between oxygen atoms, single bonds to hydrogen atoms, and 3 lone pairs on each oxygen atom.