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"Describe the hybrid orbitals used by the central atom(2$) and the type(2$) of bonds formed in SO^2. Hybridization: Number of bonds: σ π"
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Step 1
: Determine the hybridization of the central atom (Sulfur) in SO^2.

Sulfur forms three bonds in SO^2, two single bonds with oxygen atoms and one double bond with another oxygen atom. To accommodate this, sulfur will use sp^2 hybridization.

Step 2
: Explain sp^2 hybridization.

sp^2 hybridization is a combination of one s orbital and two p orbitals to form three hybrid orbitals with equal energy and geometry. The three hybrid orbitals are arranged in a trigonal planar geometry, making a 120 -degree angle with each other.

Final Answer

Hybridization: The central atom, sulfur, in SO^2 uses sp^2 hybridization. Number of bonds: Sulfur forms a total of three bonds: two σ bonds with one oxygen atom and one π bond with another oxygen atom. σ and π bonds: Sulfur forms two σ bonds and one π bond in SO^2.

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