QQuestionChemistry
QuestionChemistry
"Determine the electron geometry (eg), molecular geometry (mg) around the Oxygen atom of CH^3OH and the polarity of the whole CH^3OH molecule.
a. eg = tetrahedral, mg = linear, nonpolar
b. eg = trigonal bipyramidal, mg = trigonal planar, nonpolar
c. eg = linear, mg = linear, polar
d. eg = octahedral, mg = square planar, nonpolar
e. eg = tetrahedral, mg = bent, polar
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Answer
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Step 1Let's solve this step by step:
Step 2: Analyze the Lewis Structure of CH₃OH
- Total valence electrons: $$4 + 6 + (4 \times 1) = 14$$ electrons
- Carbon (C) has 4 valence electrons - Oxygen (O) has 6 valence electrons - Hydrogen (H) has 1 valence electron
Final Answer
\text{CH}_3\text{OH has a tetrahedral electron geometry, bent molecular geometry, and is polar}
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