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QuestionChemistry

"Draw a Lewis structure for XeF^4 and answer the following questions based on your drawing. 1. For the central xenon atom: The number of lone pairs = The number of single bonds = The number of double bonds = 2. The central xenon atom A. Obeys the octet rule B. Has an incomplete octet. C. Has an expanded octet."
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Step 1
: Draw the Lewis structure for XeF^4.

To draw the Lewis structure, place Xe in the center and surround it with F atoms. There are 6 valence electrons around Xe and 7 valence electrons around each F atom, making a total of 14 valence electrons. Xe: : F: : Now, distribute the remaining valence electrons as single bonds between Xe and F atoms. There will be 4 single bonds formed. Xe: :F: :F: :F: :F:

Step 2
: Determine the number of lone pairs, single bonds, and double bonds for the central xenon atom.

The number of lone pairs on the central xenon atom = 0 The number of single bonds on the central xenon atom = 4 The number of double bonds on the central xenon atom = 0

Final Answer

1. For the central xenon atom: - The number of lone pairs = 0 - The number of single bonds = 4 - The number of double bonds = 0 2. The central xenon atom: - Obeys the octet rule (A)

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