QQuestionChemistry
QuestionChemistry
Draw the best Lewis structure for BrO^4− and determine the formal charge on bromine.
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Answer
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Step 1I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2: Determine the total number of valence electrons
- Total valence electrons: $$7 + 24 + 1 = 32$$ electrons
- Bromine (Br): 7 valence electrons - Oxygen (O): 6 valence electrons × 4 = 24 valence electrons - Negative charge: + 1 electron
Final Answer
The Lewis structure for \text{BrO}_{4}^{-} has bromine with a formal charge of + 3, with four single bonds to oxygen atoms, and each oxygen having three lone pairs.
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