Answer
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Step 1I'll solve this Lewis structure problem step by step, following the specified formatting guidelines:
Step 2: Determine the total number of valence electrons
• Total valence electrons: $$7 + (7 \times 5) = 42$$ electrons
• Iodine (I): 7 valence electrons • Chlorine (Cl): 7 valence electrons × 5 = 35 valence electrons
Final Answer
The Lewis structure for ICl^5 consists of an iodine atom with five chlorine atoms arranged around it, with one lone pair on the central iodine and three lone pairs on each chlorine atom.
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