Answer
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Step 1: Identify the total number of valence electrons in the molecule
The given molecule is CH^2O^2, where C is carbon, H is hydrogen, and O is oxygen. The number of valence electrons for each atom is as follows: - C (carbon) has 4 valence electrons (2s^2 2p^2 configuration) - H (hydrogen) has 1 valence electron (1s^1 configuration) - O (oxygen) has 6 valence electrons (2s^2 2p^4 configuration) There are two hydrogen atoms, one carbon atom, and two oxygen atoms in the molecule. So, the total number of valence electrons in CH^2O^2 is: Total valence electrons = (2 * 1) + 4 + (2 * 6) = 18 valence electrons
Step 2: Place the atoms in the Lewis structure
Place the atoms in the Lewis structure, starting with the central atom. In this case, carbon (C) is the central atom. Then, add the remaining atoms around it. The structure will look like this: H — C — O — O
Final Answer
The Lewis structure for CH^2O^2 is: H — C — O:- O:
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