Answer
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Step 1I'll solve this Lewis structure problem step by step, following the specified LaTeX formatting guidelines:
Step 2: Determine the total number of valence electrons
Total valence electrons: $$6 + (7 \times 5) + 1 = 6 + 35 + 1 = 42$$ electrons
- Fluorine (F): 7 valence electrons × 5 fluorines
Final Answer
The Lewis structure for [SeF_{5}]^{-} will have: - Selenium at center - Five fluorine atoms bonded to selenium - Each fluorine with 6 lone pair electrons - 2 lone pairs on selenium - Single bonds between selenium and fluorines
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