Draw the Lewis structure for the azide $\left(\mathrm{N}_{3}^{-}\right)$ion.
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Answer

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Step 1
I'll solve this Lewis structure problem step by step:

Step 2
: Determine the total number of valence electrons

- Total valence electrons: $$(3 \times 5) + 1 = 16$$ electrons
- Nitrogen (N) has 5 valence electrons - We have 3 nitrogen atoms - The ion has a - 1 charge, which adds 1 more electron

Final Answer

The Lewis structure for the azide ion \left(\mathrm{N}_{3}^{-}\right) is a linear structure with triple bonds and a negative charge.