QQuestionChemistry
QuestionChemistry
Draw the Lewis structure for the molecule XeF₄. Include all lone pairs of electrons. If resonance structures are needed to describe the Lewis structure, draw all possible resonance structures.
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Answer
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Step 1I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2: Determine the total number of valence electrons
- Total valence electrons: $$8 + (4 \times 7) = 8 + 28 = 36$$ valence electrons
- Xe (Xenon) is in Group 18 and has 8 valence electrons - F (Fluorine) has 7 valence electrons
Final Answer
The Lewis structure for XeF₄ shows a square planar molecular geometry with the Xe atom in the center, four F atoms symmetrically arranged around it, with additional lone pairs as described above.
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