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QuestionChemistry

Draw the Lewis structure for the polyatomic hydroperoxy anion (HO^- 2). be sure to include all resonance structures that satisfy the octect rule.
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Step 1
: Identify the total number of valence electrons in the molecule.

The hydroperoxy anion (HO$^-2$) consists of one hydrogen atom (1 valence electron), one oxygen atom (6 valence electrons), and two extra negative charges (2 $\times$ 6 = 12 valence electrons).
Therefore, the total number of valence electrons in the molecule is 1 + 6 + 12 = 19 valence electrons.

Step 2
: Determine the central atom and arrange the remaining atoms around it.

In this case, oxygen is the central atom, and hydrogen is attached to it. Place the hydrogen atom and the negative charges on opposite sides of the oxygen atom.

Final Answer

The Lewis structure for the hydroperoxy anion (HO$^- 2$) includes the following resonance structures: \begin{array}{ccc} \text{Structure 1:} & \text{Structure 2:} & \text{Structure 3:} \ \chemfig{H-O=-(-[:90]O)^{-}} & \chemfig{H-O=O(-[:90]O)^{-}} & \chemfig{O=-(-[:90]O)^{-}-H} \end{array} These structures represent the delocalization of the negative charges in the molecule.

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