Q
QuestionChemistry

Draw the Lewis structure for xenon tetrafluoride (XeF₄). How many valence electrons surround the central Xe atom in this structure?
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Answer

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Step 1
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Step 2
: Determine Total Valence Electrons

- Total valence electrons: $$8 + (7 \times 4) = 8 + 28 = 36$$ valence electrons
- F (fluorine): 7 valence electrons × 4 fluorine atoms

Final Answer

12 valence electrons surround the central Xe atom in XeF₄.