QQuestionChemistry
QuestionChemistry
"Draw the Lewis structure of HCN. Include lone pairs."" is a complete question. It clearly asks for:
The Lewis structure of hydrogen cyanide (HCN).
That lone pairs should be shown."
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Answer
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Step 1: Identify the number of valence electrons in each atom
1 \ \text{valence electron (H)} + 5 \ \text{valence electrons (N)} + 5 \ \text{valence electrons (C)} = 11 \ \text{valence electrons}
Hydrogen (H) has 1 valence electron, and nitrogen (N) and carbon (C) each have 5 valence electrons. Since there is one H atom, one N atom, and one C atom, the total number of valence electrons is:
Step 2: Place the atoms in the Lewis structure
Place the H atom and C atom next to each other, followed by the N atom. Connect them with a single bond, which uses 2 valence electrons: H - C - N
Final Answer
The Lewis structure of HCN with lone pairs is: H : C ::: N: The formal charges are all 0, and the octet rule is satisfied for all atoms.
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