Q
QuestionChemistry

Draw the Lewis structure of NH^4 + and determine its geometry, bond angle, and the hybridization of the N atom.
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Answer

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Step 1
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Step 2
: Determine the total number of valence electrons

Total valence electrons: $$5 + 4 - 1 = 8$$ electrons
- Nitrogen (N): 5 valence electrons - Hydrogen (H): 1 valence electron × 4 hydrogens = 4 electrons - Positive charge removes 1 electron

Final Answer

- Lewis Structure: Tetrahedral NH^4 + with 4 single N-H bonds - Geometry: Tetrahedral - Bond Angle: 109.5° - Nitrogen Hybridization: sp^{3}