Draw the Lewis structure of SF₂ showing all lone pairs. What is the hybridization of the central atom? - sp - sp² - sp³ - sp³d - sp³d² An SF₂ molecule is - polar. - nonpolar. Identify the molecular geometry of SF₂. - trigonal bipyramidal - bent - tetrahedral - square planar - square pyramidal - trigonal pyramidal - T-shaped - linear - trigonal planar - see-saw - octahedral What is the approximate bond angle in SF₂? - 90 degrees - 105 degrees - 120 degrees - 180 degrees
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Answer

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Step 1
: Draw the Lewis structure of SF₂

To draw the Lewis structure of SF₂, we first need to determine the total number of valence electrons. A sulfur atom (S) has 6 valence electrons, and each fluorine atom (F) has 7 valence electrons. Since there are two fluorine atoms, the total number of valence electrons is: \text{Total valence electrons} = 6\ (\text{S}) + 2 \times 7\ (\text{F}) = 20 Now, let's distribute these electrons around the atoms. Sulfur is the central atom, and it shares one electron with each fluorine atom, forming two single bonds. This uses up 4 of the valence electrons. The remaining 16 electrons will be placed as lone pairs on the fluorine atoms and the sulfur atom to complete their octets: \chemfig{S(-[:150]F)(-[:210]F)}

Step 2
: Determine the hybridization of the central atom

Thehybridizationofthecentralatomcanbedeterminedbycountingthenumberofelectrondomains(σbondsandlonepairs)aroundit.Inthiscase,sulfurhastwoσbondsandonelonepair,resultinginatotalof3electrondomains.Thehybridizationofthecentralatomissp2:Hybridization=sp2The hybridization of the central atom can be determined by counting the number of electron domains (σ bonds and lone pairs) around it. In this case, sulfur has two σ bonds and one lone pair, resulting in a total of 3 electron domains. The hybridization of the central atom is sp²: \text{Hybridization} = \boxed{\text{sp}^2}

Final Answer

1. Lewis structure: \chemfig{S(-[:150]F)(-[:210]F)} 2. Hybridization: sp² 3. Polarity: nonpolar 4. Molecular geometry: bent 5. Approximate bond angle: 105 degrees

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