QQuestionChemistry
QuestionChemistry
Draw the structure of bromous acid, [tex]HBrO^2[/tex]. Optimize formal charges.
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Answer
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Step 1I'll solve this problem step by step, following the LaTeX formatting guidelines precisely:
Step 2: Determine the number of valence electrons
Total valence electrons: $$1 + 7 + (2 \times 6) = 20$$ valence electrons
- Hydrogen (H): 1 valence electron - Bromine (Br): 7 valence electrons - Oxygen (O): 6 valence electrons
Final Answer
The Lewis structure of bromous acid HBrO_{2} has: - Bromine as central atom - Symmetric arrangement with zero formal charges - Hydrogen attached to one oxygen - Double bond between bromine and one oxygen - Single bond between bromine and other oxygen - Lone pairs on oxygen atoms to satisfy octet rule
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