QQuestionChemistry
QuestionChemistry
Draw two Lewis structures for a compound with the formula C^4H^10. No atom bears a charge, and all carbon atoms have complete octets.
6 months agoReport content
Answer
Full Solution Locked
Sign in to view the complete step-by-step solution and unlock all study resources.
Step 1I'll solve this Lewis structure problem step by step:
Step 2: Determine the total number of valence electrons
- Total valence electrons: $$(4 \times 4) + (10 \times 1) = 16 + 10 = 26$$ valence electrons
- Carbon (C) has 4 valence electrons - Hydrogen (H) has 1 valence electron
Final Answer
Two valid Lewis structures for C^4H^10 are n-butane and isobutane, each satisfying the requirements of no charged atoms and complete octets for carbon atoms.
Need Help with Homework?
Stuck on a difficult problem? We've got you covered:
- Post your question or upload an image
- Get instant step-by-step solutions
- Learn from our AI and community of students