Equation 1: x minus y, equals 1. Equation 2: x plus y equals, x squared minus 3 Which ordered pair is a solution to the system of equations above? A. 1 plus the square root of 3, comma, the square root of 3 B. 1 plus the square root of 3, comma, the negative of the square root of 3 C. 1 plus the square root of 5, comma, the square root of 5 D. 1 plus the square root of 5, comma, negative 1 plus the square root of 5
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Answer

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Step 1
: Identify the given system of equations.

Equation 2: $$x + y = x^2 - 3

Step 2
: To check which ordered pair is a solution to the system of equations, substitute the values of both x and y from each option into both equations and verify if they hold true.

(1 + \sqrt{3}) + \sqrt{3} = 1 + 2\sqrt{3} \neq (1 + \sqrt{3})^2 - 3$$ (since $$(1 + \sqrt{3})^2 - 3 = 4$$)
Checking Equation 1: Checking Equation 2: So, option A is not a solution.

Final Answer

The ordered pair (1 + √5, √5) is a solution to the given system of equations.