For each atom in the table below, write down the subshell from which an electron would have to electron would have to be added to make a - 1 anion. The first row has been completed for you. | atom | subshell from which electron removed to form + 1 cation | subshell to which electron added to form - 1 anion | | --- | --- | --- | | H | 1x | 1x | | C | | | | Ti | | | | Ar | | |
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Answer

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Step 1
: To determine the subshell to which an electron must be added to form a - 1 anion, we need to find the outermost subshell in each atom.

This is the subshell that can accommodate one more electron to complete the octet and form a stable - 1 anion.

Step 2
: For Carbon (C), the atomic number is 6, and its electron configuration is 1s^2 2s^2 2p^2.

The outermost subshell is $$2p$$.
Therefore, an electron must be added to the 2p subshell to form a - 1 anion.

Final Answer

| atom | subshell from which electron removed to form + 1 cation | subshell to which electron added to form - 1 anion | | --- | --- | --- | | H | 1s | 1s | | C | 2s or 2p | 2p | | Ti | 4s or 3d or 4p | 4d | | Ar | 3p | 3p | Note: For Carbon, either the 2s or 2p subshell can be used to form a + 1 cation, depending on the specific chemical reaction. Similarly, for Titanium, either the 4s, 3d, or 4p subshell can be used to form a + 1 cation, depending on the specific chemical reaction.