Q
QuestionChemistry

"For the compound BH^3, show the following: (i) Lewis electron dot formula (ii) Lewis structure (draw in 3D - use wedge and dash for tetrahedral) (iii) Electronic geometry (name) (iv) Molecular geometry (name) (v) Bond angle (ideal) (vi) Polar or non-polar"
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Answer

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Step 1
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Step 2
: Lewis Electron Dot Formula

- Total valence electrons: $$3 + (3 \times 1) = 6$$ electrons
- Boron (B) has 3 valence electrons - Hydrogen (H) has 1 valence electron

Final Answer

(i) Lewis dot formula: \begin{array}{c} H \cdot \ \text{} \mid \ B \cdot - H \ \text{} \mid \ H \cdot \end{array} (ii) 3D Lewis structure with wedge/dash (iii) Tetrahedral electronic geometry (iv) Trigonal planar molecular geometry (v) 120^{\circ} bond angle (vi) Polar molecule