QQuestionChemistry
QuestionChemistry
Give the bond order and number of unpaired electrons in C^2 molecule and N^2 - ion.
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Answer
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Step 1
- For N atom: $$1s^2 2s^2 2p^3
First, let's write the electron configuration for each atom in the molecule/ion:
Step 2
<td>$$2p^3$$ (two electrons in one orbital, one electron in each of the other two)</td>
Now, let's determine the molecular orbital diagram for each species. - For C^2 molecule: <table> <tr> <th></th> <th>C atom 1</th> <th>C atom 2</th> </tr> <tr> <td>1s</td> </tr> <tr> <td>2s</td> </tr> <tr> <td>2p</td> </tr> </table> The overlapping of the 2p orbitals creates molecular orbitals (MOs). The bonding MO has lower energy than the atomic orbitals, and the antibonding MO has higher energy. Each MO can hold up to 2 electrons with opposite spins. - For N^2 - ion: <table> <tr> <th></th> <th>N atom 1</th> <th>N atom 2</th> </tr> <tr> <td>1s</td> </tr> <tr> <td>2s</td> </tr> <tr> <td>2p</td> </tr> </table> Again, overlapping of the 2p orbitals creates bonding and antibonding MOs.
Final Answer
- The bond order for C^2 molecule is 2, and there are no unpaired electrons. - The bond order for N^2 - ion is 2, and there are 2 unpaired electrons.
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