One solution to the given equation can be written as $1 +\sqrt{k}$, where $k$ is a constant. What is the value of $k$ ? A. 8 B. 10 C. 20 D. 40
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Answer

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Step 1
: First, we need to square both sides of the equation since the given solution is in the form $1 +\sqrt{k}$.

(1+k)2=(some constant)2(1+\sqrt{k})^2 = (\text{some constant})^2
This will eliminate the square root.

Step 2
: Expand the left side of the equation using the formula for squaring a binomial.

1+2k+k=(some constant)21 + 2\sqrt{k} + k = (\text{some constant})^2

Final Answer

Choice (D) is correct.