**Question:** The chemical formula for lead(II) nitrite is: Pb(NO₂)₂. How many oxygen atoms are in each formula unit of lead(II) nitrite? The chemical formula for lead(II) nitrite is: Pb(NO_2)_2 How many oxygen atoms are in each formula unit of lead(II) nitrite?
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Step 1
**Step 1:** Identify the number of oxygen atoms in the nitrite ion, NO^2.-

The nitrite ion has one nitrogen atom and two oxygen atoms. This is represented by the subscript 2 in the formula NO^2 -. **Step 2:** Examine the subscript of the nitrite ion in the overall formula for lead(2$) nitrite. In the formula for lead(2$) nitrite, there are two nitrite ions present, as indicated by the subscript 2 after NO^2 -. **Step 3:** Multiply the number of oxygen atoms in the nitrite ion by the number of nitrite ions in the formula. Since there are 2 oxygen atoms in each nitrite ion, and there are 2 nitrite ions in the formula for lead(2$) nitrite, there are a total of 2 x 2 = 4 oxygen atoms in each formula unit of lead(2$) nitrite. **

Final Answer

** There are 4 oxygen atoms in each formula unit of lead(II) nitrite.