# 2 Lessons $\odot$ Assessments $\checkmark$ Gradebook $\square$ Email Tools $\cdot$ ## 4 Add Audio $\rightarrow$ Add Video ## Question 14 (Essay Worth 12 points) ## (Two-Step Linear Inequalities HC) The inequality $- 6(x- 3)>42$ is given. Part A: Solve the inequality and show every step of your work. (4 points) Part B: Explain in words how to graph the solution to the inequal on a number line. (4 points) Part C: Find two values that would make the inequality true. Explain how you know the values are solutions to the inequality. (4 points) $- 6(x- 3)>42$ add 3 to both sides $3 +- 3 = 042 + 3 = 45 \quad- 6 x>42$ divide 42 by $- 642 \div- 6 =- 7$ Finally, flip the sign because we divided it by a negative number, so the answer is $x<- 7$. I would graph an open circle from - 7 going left as $x$ is less than - 7 .
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Answer

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Step 1
: Solve the inequality.

x < -7 \quad \color{blue}{\text{Simplify the right side}}

Step 2
: Explain in words how to graph the solution on a number line.

The open circle indicates that $-7$ is not a solution, and the shading to the left shows that all values less than $-7$ are solutions.

Final Answer

Part A: The solution to the inequality is $x < - 1$. Part B: To graph the solution on a number line, put an open circle at $- 1$ and shade all numbers to the left. Part C: Two values that make the inequality true are $- 1$ and $- 1$.