QQuestionAnatomy and Physiology
QuestionAnatomy and Physiology
An 80.0 -kg object is falling and experiences a drag force due to air resistance. The magnitude of this drag force depends on its speed, , and obeys the equation. What is the terminal speed of this object?
| 72.2 m/s | |
| --- | --- |
| 12.6 m/s | |
| 47.3 m/s | |
| 34.2 m/s | |
| 6.45 m/s | |
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Answer
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Step 1: Recall the equation for the drag force, which is given as F\_D = kv^2.
The terminal speed, denoted by $$v\_t$$, is the constant speed at which the net force acting on the object becomes zero.
At the terminal speed, the drag force equals the gravitational force, i.e., F\_D = F\_G. We can set these two forces equal to each other and solve for the terminal speed.
Step 2: The gravitational force on an object is given by the equation F\_G = mg, where m is the mass of the object and g is the acceleration due to gravity.
Substituting this equation into the net force equation, we get $$kv\_t^2 = mg$$.
Final Answer
The terminal speed of the object is 72.2 m/s.
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