QQuestionAnatomy and Physiology
QuestionAnatomy and Physiology
At what two points between object and screen may a converging lens with a 3.80 cm focal length be placed to obtain an image on the screen?
Express your answers in centimeters separated by a comma. Count the distances from the object.
## Part B
What is the magnification of the image for each position of the lens?
Express your answer as two numbers, separated by a comma.
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Step 1: Set up the thin lens equation
We are given the focal length $$f = 3.80 \, \text{cm}$$.
We need to find the two positions where the lens can be placed such that an image is formed on the screen. This means that the image distance will always be positive.
Step 2: Solve for the image distance (d_{i}) in terms of the object distance (d_{o})
d_{i} = \left(\frac{1}{f} - \frac{1}{d_{o}}\right)^{-1}
Final Answer
The two positions of the lens are: d_{o^1} = \boxed{????} \, \text{cm} d_{o^2} = \boxed{????} \, \text{cm} The magnifications for these positions are: m_{1} = \boxed{????} m_{2} = \boxed{????} Since the problem does not provide specific values for the object distance, we cannot provide exact numerical answers. Instead, we have shown the formulas and steps to find the two positions of the lens and their corresponding magnifications. To find the actual values, substitute the given focal length and the appropriate object distances into the formulas from Steps 3, 4, and 5.
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