Dee Wallace's salary was $58,900 in 2003 and increased to $64,900 in 2008. What was the annual rate of change in his salary?
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Answer

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Step 1
: Determine the change in salary over the given time period.

\Delta \text{salary} = \$64,900 - \$58,900 = \$6,000
The change in salary is the difference between the final salary and the initial salary:

Step 2
: Calculate the number of years between 2003 and 2008.

\Delta t = 2008 - 2003 = 5 \text{ years}

Final Answer

The annual rate of change in Dee Wallace's salary from 2003 to 2008 was $1,200.