Determine which is the larger species. $\bigcirc \mathrm{K}^{+}$ $\bigcirc \mathrm{K}$ Determine which is the larger species. $\bigcirc \mathrm{O}$ $\bigcirc \mathrm{O}^{2 -}$ Determine which is the larger species. $\bigcirc \mathrm{O}^{2 -}$ $\bigcirc \mathrm{Na}^{+}$
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Step 1
: Recall that ions are atoms or molecules that have gained or lost electrons, resulting in a net charge.

The size of an ion is influenced by its charge and the number of electrons in its outermost energy level.

Step 2
: Compare the sizes of $\mathrm{K}^{+}$ and $\mathrm{K}$.

Potassium $\mathrm{K}$ is an alkali metal with one electron in its outermost energy level.
When it loses this electron to form $\mathrm{K}^{+}$, the remaining electrons occupy a smaller volume, making the $\mathrm{K}^{+}$ ion smaller than the neutral $\mathrm{K}$ atom.

Final Answer

Step 3: Compare the sizes of $\mathrm{O}$ and $\mathrm{O}^{2 -}$. Oxygen is a chalcogen with six electrons in its outermost energy level. When it gains two electrons to form $\mathrm{O}^{2 -}$, the added electrons occupy a larger volume, making the $\mathrm{O}^{2 -}$ ion larger than the neutral $\mathrm{O}$ atom. Step 4: Compare the sizes of $\mathrm{O}^{2 -}$ and $\mathrm{Na}^{+}$. Sodium $\mathrm{Na}$ is an alkali metal with one electron in its outermost energy level. When it loses this electron to form $\mathrm{Na}^{+}$, the remaining electrons occupy a smaller volume. Oxygen $\mathrm{O}^{2 -}$ has gained two electrons, causing the added electrons to occupy a larger volume. As a result, the $\mathrm{O}^{2 -}$ ion is larger than the $\mathrm{Na}^{+}$ ion.