Draw the Lewis structure of chloroform, also called trichloromethane, $\left(\mathrm{CHCl}_{3}\right)$ and then determine the ideal bonding angle(s) of the central atom. A) $180^{\circ}$ B) $90^{\circ}$ and $120^{\circ}$ C) $109.5^{\circ}$ D) $120^{\circ}$ E) $135^{\circ}$
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Answer

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Step 1
: Draw the Lewis structure of chloroform, $\left(\mathrm{CHCl}_{3}\right)$.

To draw the Lewis structure, we need to follow these steps:

Step 2

Count the total number of valence electrons for the molecule. Chlorine (Cl) has 7 valence electrons, and hydrogen (H) has 1 valence electron. The central atom, carbon (C), has 4 valence electrons. So, the total number of valence electrons is: \text{Total valence electrons} = 4 \text{(C)} + 1 \text{(H)} + 7 \times 3 \text{(Cl)} = 28 \text{ valence electrons}

Final Answer

So, the correct answer is option (C).