QQuestionAnatomy and Physiology
QuestionAnatomy and Physiology
If (S)-glyceraldehyde has a specific rotation of $- 8.7^{\circ}$, what is the specific rotation of (R)glyceraldehyde?
$\bigcirc+ 8.7^{\circ}$
$\bigcirc- 8.7^{\circ}$
$\bigcirc 0.0^{\circ}$
$\bigcirc$ cannot be determined from the information given
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Answer
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Step 1: Understand the problem
We are given the specific rotation of (S)-glyceraldehyde and asked to find the specific rotation of (R)-glyceraldehyde. The specific rotation of an optically active compound is a physical property that describes the magnitude and direction of its rotation of plane-polarized light.
Step 2: Recall relevant concepts and formulas
where $[\alpha]_{text{(R)}}$ is the specific rotation of the (R)-enantiomer and $[\alpha]_{text{(S)}}$ is the specific rotation of the (S)-enantiomer.
The specific rotation of an enantiomer is related to the specific rotation of its mirror image (enantiomer) through the relationship:
Final Answer
The specific rotation of (R)glyceraldehyde is $8.7^{\circ}$.
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