# Solve for $x$. 2^{x+ 5}= 13^{2 x} Write the exact answer using either base- 10 or base-e logarithms.
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Answer

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Step 1
: To solve the equation, we will take the base- 10 logarithm (log) of both sides.

This is a valid operation since logarithms and exponentials are inverse operations. \log_{10}\left(2^{x+ 5}\right) = \log_{10}\left(13^{2x}\right)

Step 2
: Using the power rule for logarithms, which states that 1$, we can rewrite the equation as:

(x+ 5)\log_{10}(2) = 2x\log_{10}(13)

Final Answer

The solution to the equation 1$.