QQuestionStatistics
QuestionStatistics
Suppose T and Z are random variables
How do I solve this?
a) if P(t>2.17)= 0.04 and P(t<- 2.17)= 0.04 obtain P(- 2.17<=T<= 2.17)
b) If P (- 1.18 <=Z<= 1.18)= 0.76 and also P(Z>1.18)=P(Z<- 1.18) Find P(Z>1.18)
5 months agoReport content
Answer
Full Solution Locked
Sign in to view the complete step-by-step solution and unlock all study resources.
Step 1
P(-2.17 \leq T \leq 2.17) = 1 - [0.04 + 0.04] = 1 - 0.08 = \boxed{0.92}.
We know that $P(T > 2.17) = 0.1$ and $P(T < - 2.17) = 0.1$. Thus, Using the union bound, we have Now, we can substitute the given values:
Step 2
P(Z > 1.18) = \frac{1 - 0.76}{2} = \boxed{0.07}.
We want to find $P(Z > 1.18)$. Since the total probability is 1, we have
Final Answer
P(Z > 1.18) = \frac{1 - 0.76}{2} = \boxed{0.07}.
Need Help with Homework?
Stuck on a difficult problem? We've got you covered:
- Post your question or upload an image
- Get instant step-by-step solutions
- Learn from our AI and community of students