What does mean a 94% enantiomeric excess? - ☐ The product contains 94% of one enantiomer and 6% of the other enantiomer - ☐ The product contains 94% of one enantiomer and 6% of other products - ☐ The product contains an enantiomer which is 94% pure. - ☐ The product contains 97% of one enantiomer and 3% of the other enantiomer
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Answer

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Step 1
: Understand the concept of enantiomeric excess

Enantiomeric excess (ee) is a measure used in stereochemistry to describe the purity of a mixture of two enantiomers. Enantiomers are stereoisomers that are mirror images of each other and cannot be superimposed. A 94% enantiomeric excess means that the mixture contains 94% of one enantiomer and 6% of the other enantiomer.

Step 2
: Analyze the answer choices

Let's examine the given answer choices and determine which one accurately describes a 94% enantiomeric excess: A. The product contains 94% of one enantiomer and 6% of the other enantiomer This answer choice is correct, as it accurately describes a 94% enantiomeric excess. B. The product contains 94% of one enantiomer and 6% of other products This answer choice is incorrect because it implies that the 6% contains other products, not the other enantiomer. C. The product contains an enantiomer which is 94% pure. This answer choice is incorrect because it implies that the 94% refers to the purity of a single enantiomer, not the mixture. D. The product contains 97% of one enantiomer and 3% of the other enantiomer This answer choice is incorrect because it describes a different enantiomeric excess (97% vs. 94%).

Final Answer

The product contains 94% of one enantiomer and 6% of the other enantiomer.