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QuestionChemistry

Sodium iodide has a molar mass of 149.89 g/mol. To prepare 750 mL of 0.1 M NaI, using acetone as your solvent, what mass of NaI is required?
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Step 1
: Determine the number of moles of sodium iodide (NaI) needed.

To prepare 750 mL of 0.1 M NaI solution, we first need to find out how many moles of NaI are required. We can do this by multiplying the volume of the solution by its molarity. Moles of NaI = Volume (L) x Molarity (M) Moles of NaI = 0.750 L x 0.1 M

Step 2
: Calculate the mass of NaI required.

Now that we have the number of moles, we can calculate the mass of NaI needed using the molar mass of NaI (149.89 g/mol). Mass of NaI = Moles of NaI x Molar mass (g/mol) Mass of NaI = 0.075 mol x 149.89 g/mol

Final Answer

To prepare 750 mL of 0.1 M NaI solution, you will need 11.24 g of sodium iodide (NaI).

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