70n3(70n4)2 \sqrt[3]{70 n}(\sqrt[4]{70 n})^{2}
For what value of $x$ is the given expression equivalent to $(70 n)^{20 x}$, where $n>1$ ?
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Answer

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Step 1
: Recognize that the given expression is a cube root and a fourth power multiplied together.

70n3×(70n4)2\sqrt[3]{70 n} \times (\sqrt[4]{70 n})^2

Step 2
: To make the base of both radicals the same, we can rewrite the fourth root as a cube root and a remaining fourth power.

(70n3)×(70n)24(\sqrt[3]{70 n}) \times (70 n)^{\frac{2}{4}}

Final Answer

The given expression is equivalent to $(70 n)^{20x}$ when $x = \boxed{\frac{1}{24}}$.