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QuestionChemistry

The atomic number of lead (Pb) is 82, and its mass number is 207. How many protons, neutrons, and electrons does this neutral atom of lead (Pb) contain?
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Answer

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Step 1
: Determine the number of protons in a lead atom

Theatomicnumberofleadis82,whichmeansthereare82protonsinaneutralatomoflead.Number of protons=82The atomic number of lead is 82, which means there are 82 protons in a neutral atom of lead. \boxed{\text{Number of protons} = 82}

Step 2
: Determine the number of neutrons in a lead atom

Themassnumberofleadis207.Sincethemassnumberincludesthenumberofprotonsandneutrons,wecancalculatethenumberofneutronsbysubtractingthenumberofprotonsfromthemassnumber.Number of neutrons=Mass number−Number of protonsNumber of neutrons=207−82Number of neutrons=125The mass number of lead is 207. Since the mass number includes the number of protons and neutrons, we can calculate the number of neutrons by subtracting the number of protons from the mass number. \text{Number of neutrons} = \text{Mass number} - \text{Number of protons} \text{Number of neutrons} = 207 - 82 \boxed{\text{Number of neutrons} = 125}

Final Answer

A neutral atom of lead (Pb) contains 82 protons, 125 neutrons, and 82 electrons.

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