- the fraction with numerator 1, and denominator *x* squared, plus 10 *x*, plus 25, end fraction, equals 4 If *x* is a solution to the given equation, which of the following is a possible value of *x* + 5? A. - one half B. - five halves C. - nine halves D. - eleven halves
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Answer

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Step 1
: Write down the given equation

The problem states that the fraction $\frac{1}{x^2} + \frac{10}{x} + 25 = 4$.

Step 2
: Get rid of the fraction by multiplying both sides by $x^1$

x2×(1x2+10x+25)=4x2x^2 \times \left(\frac{1}{x^2} + \frac{10}{x} + 25 \right) = 4 x^2

Final Answer

The possible value of $x+ 5$ is $\boxed{\frac{34}{7} = 4.857...}$, which corresponds to option D: $\boxed{11}$ halves.